Above: Section from "5300"
Above: Section from "5500"
©TK Boyd 2/12
©TK Boyd 2/12
That's a lot of zebra.... here's a subsection of the above....
©TK Boyd 2/12
But! How many zebra, some of you will ask. (Those of you who haven't wondered, and have not wondered how you would count them, or are asking why anyone would care, can stop reading here!)
Here's one approach....
Take samples of the overall picture. Count the zebra in the samples.
How you sample the picture will have a big effect on the accurarcy of your count.
It was 6560 units wide in PhotoPlus, the photo editor I use.
I took a 208 unit sample of the whole picture every 600 units along, i.e. the first sample was from 0-208, the second was from 600-808, etc.
Sorry about the fuzzy edges to the samples. And the strange number (208). Feel free to re-do the sampling work!
Here are the samples. See if you can get a number for the whole view if you want to. Or read on (below samples) for further discussion...
Above: Section from "5300"
Above: Section from "5500"
... if you want to "do it yourself
Otherwise....
... read on....
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I "cheated" with one sample.... the one for "from 5300". There's a big bush in most of that image, so, having looked either side of the bush in the overall image and found roughly equal numbers of zebra either side of it, I assumed that there were a similar number behind the bush, and counted the sample starting at 5500. The "5300" and "5500" samples are available to you, above.
Count the zebra in the samples. Do the arithmetic. That will give you an approximation of the number of zebra in the scene.
I'll try to come back to this one day and finish the arithmetic and discussion for you!
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Sample / My count of zebra in sample 0000 3 0600 16 1200 8 1800 16 2400 16 3000 15 3600 13 4200 15 4800 7 (5300)- not counted 5500 15 6000 2
As I said... I'll try to come back, finish this one day!.... Especially if SOMEONE writes me, and says "That was fun". It has ben quite a bit of work to put it together for you!
Draft of "rest".....
Average zebra in sample: 11.45 Whole view/ sample: 6560/208= 31.54 Estimate for number of zebra: 31.54 x 11.45 ..... about 360.
... and remember: this was just one of many groups in the area.
This page © TK Boyd 2/11. Click here to contact him.
You are also invited to Tom Boyd's homepage, including software for schools, kids, and others.
Page will be tested for compliance with INDUSTRY (not MS-only) standards, using the free, publicly accessible validator at validator.w3.org. An early draft of the page was valid apart from several things inside the code to embed the video clip of the ocelots.
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